Q) A garden is in the shape of a square. The gardener grew saplings of Ashoka tree on the boundary of the garden at the distance of 1 m from each other. He wants to decorate the garden with rose plants. He chose a triangular region inside the garden to grow rose plants. In the above situation, the gardener took help from the students of class 10. They made a chart for it which looks like the given figure.

A garden is in the shape of a square. The gardener grew saplings of Ashoka tree 10th board exam CBSE PYQs 2024

Based on the above, answer the following questions :
(i) If A is taken as origin, what are the coordinates of the vertices of Δ PQR?
(ii) Find distances PQ and QR.
(iii) Find the coordinates of the point which divides the line segment joining points P and R in the ratio 2 : 1 internally.
(iv) Find out if D PQR is an isosceles triangle.

Ans:

(i) coordinates of the vertices of Δ PQR:

from the diagram, if we take A as origin, we get following:

Coordinates of point P: (4, 6)

Coordinates of point Q: (3, 2)

Coordinates of point R: (6, 5)

(ii) Distances PQ and QR:

We know that the distance between two points P (X1, Y1) and Q (X2, Y2) is given by:

PQ = \sqrt {(\times_2 - \times _1)^2 + (Y_2 - Y_1)^2}

From the diagram, we have co-ordinates as P (4, 6) and Q (3, 2)

∴ Distance PQ = \sqrt{(3 - 4)^2 + (2 - 6)^2}

∴ PQ = \sqrt{1 + 16}

∴ PQ = √17

∴ PQ = √17 units

Similarly, from the diagram, we have co-ordinates as Q (3, 2) and R (6, 5)

∴ Distance QR = \sqrt{(6 - 3)^2 + (5 - 2)^2}

∴ QR = \sqrt{9 + 9}

∴ QR = √18

∴ QR = 2√3 units

Therefore, the length of PQ is √17 units and QR is 2√3 units.

(iii) coordinates of the point dividing the line PR in the ratio 2 : 1 internally:

By section formula, coordinates of point P (X, Y) which lies between two points (x1, y1), (x2, y2) will be given by:

P (X,Y) = (\frac{m_1 \times_2 + m_2 \times_1}{m_1 + m_2}, \frac{m_1 Y_2 + m_2 Y_1}{m_1 + m_2})

From the given diagram, we have coordinates of points P (4, 6) and R (6, 5)

Since, the point divides the line in ratio of 2:1, therefore m1 = 2 and m2 = 1

P (X,Y) = (\frac{(2)(6) + (1)(4)}{2 + 1}, \frac{(2)(5) + (1)(6)}{2 + 1})

= (\frac{16}{3}, \frac{16}{3})

Therefore, the coordinates of the point is (\frac{16}{3}, \frac{16}{3}) which divides line AB in ratio of 2:1.

(iv) Is Δ PQR an isosceles triangle?:

If Δ PQR is an isosceles triangle, then its two sides will be equal.

Coordinates of all 3 vertices are: P(4, 6), Q(3, 2) and R(6, 5)

Therefore, let’s check length of all the 3 sides:

We know that the distance between two points P (X1, Y1) and Q (X2, Y2) is given by:

\sqrt {(\times_2 - \times _1)^2 + (Y_2 - Y_1)^2}

PQ = √17 units (from part (ii) above)

QR = 2√3 units (from part (ii) above)

PR = \sqrt{(6 - 4)^2 + (5 - 6)^2}

∴ PR = \sqrt{4 + 1}

∴ PR = √5 units

Since all 3 sides are unequal, therefore Δ PQR is NOT an isosceles triangle.

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