Q) The perimeter of a rectangular park is 120 m, and its length is 10 m more than its width. Find the dimensions of the park.

Ans:

Step 1: Let the width of the park be X meters.

Since the length is 10 meters more than the width:

Length = X + 10

Step 2: The perimeter of a rectangle is given by:

P = 2 (Length + Width)

Given that Perimeter = 120 meters

∴ 120 = 2 (Length + Width)

∴ (Length + Width) = 60 …….. (i)

Step 3: By substituting values of Length and width in equation (i), we get:

(Length + Width) = 60

∴ ((X + 10) + X) = 60

∴ (2 X + 10) = 60

∴ 2 X = 60 – 10 = 50

∴ X = = 25 meters

Step 4: Since width, X = 25 meters

∴ Length = X + 10 = 25 + 10 = 35 meters

Therefore, the dimensions of the park are 25 m and 35 m.

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