Q) If the system of linear equations 2 x + 3 y = 7 and 2 a x + (a + b) y = 28 have an infinite number of solutions, then find the values of ‘a’ and ‘b’.

Ans:

Step 1: We know that the standard form of a linear equation is: a x + b y + c = 0

Given 1st linear equation is: 2 x + 3 y = 7

In standard form, it can be written as: 2 x + 3 y – 7 = 0

Comparing it with standard form, we get:

a1 = 2; b1 = 3; c1 = – 7

Similarly, when we compare 2nd linear equation (given) with standard form of equation, we get:

2 a x + (a + b) y = 28

or 2 a x + (a + b) y – 28 = 0

Therefore,  a2 = 2 a ; b2 = (a + b) ; c2 = – 28

Step 2: Next we know, that when a system of linear equations has infinite solutions, then

\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}

\frac{2}{2a} = \frac{3}{a + b} = \frac{- 7}{- 28}

\frac{1}{a} = \frac{3}{a + b} = \frac{1}{4}

Step 3: solving 1st and 3rd equations, we get:

\frac{1}{a} = \frac{1}{4}

∴ a = 4

Next, we take 2nd and 3rd equations, we get:

\frac{3}{a + b} = \frac{1}{4}

∴ a + b = 12

∴ 4 + b = 12

∴ b = 12 – 4 = 8

Therefore, the values are a = 4 and b = 8.

Please press the “Heart” button if you like the solution.

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top