Q) The interior of a building is in the form of a cylinder of base radius 12 m and height 3.5 m surmounted by a cone of equal base and slant height 14 m. Find the internal curved surface area of the building.

Ans. Let’s draw the diagram for the given question:

The interior of a building is in the form of a cylinder of base radius 12 m

Now the curved surface area of the building

= curved surface area of the cylinder + curved surface area of the Cone

= 2 π R H + π R L = π R (2 H + L)

By transferring the values, we get:

Curved surface area of the building

= (\frac{22}{7}) (12)(2 \times 3.5 + 14)

= (\frac{22}{7}) (12)(7 + 14)

= (\frac{22}{7}) (12)(21)

= 22 x 12 x 3 = 792 m2

Since here the thickness of the building wall is not given, we will assume the external curved surface area of the building and internal curved surface area of the building are equal.

Therefore, the internal curved surface area of the building is 792 m2.

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