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Q: A group of students of class X visited India Gate on an education trip. The teacher and students had interest in history as well. The teacher narrated that India Gate, official name Delhi Memorial, originally called All-India War Memorial, monumental sandstone arch in New Delhi, dedicated to the troops of British India who died in wars fought between 1914 and 1919. The teacher also said that India Gate, which is located at the eastern end of the Rajpath (formerly called the Kingsway), is about 138 feet (42 metres) in height.

A group of students of class

1. What is the angle of elevation if they are standing at a distance of 42m away from the monument?

a) 300               b) 450              c) 600                 d) 00

2. They want to see the tower at an angle of 60o. So, they want to know the distance where they should stand and hence find the distance.

a) 24.25 m.       b) 20.12 m.           c) 42 m.             d) 24.64 m

3. If the altitude of the Sun is at 60o, then the height of the vertical tower that will cast a shadow of length 20 m is

a) 20√3 m.         b) A group of students of class m.        c) A group of students of class m.        d) 15√3 m

4. The ratio of the length of a rod and its shadow is 1:1. The angle of elevation of the Sun is

a) 300                       b) 450                            c) 600                          d) 900

5. The angle formed by the line of sight with the horizontal when the object viewed is below the horizontal level is

a) corresponding angle.                  b) angle of elevation.         

c) angle of depression.                    d) complete angle

Ans:

1. Angle of elevation at  42 m distance:

A group of students of classHeight AB = 42 m

Distance from the base, BC = 42 m

Now, ∠ ACB is A group of students of class,

A group of students of class

By substituting values in above equation, we get:

A group of students of class

∵ we know that tan 450 = 1

∴  A group of students of class

A group of students of class = 450

Hence, option b) is correct.

2. Distance from base when angle is 600: 

A group of students of classFrom the adjoining figure, we can see that in ∆ ABC,

Given that the Height AB = 42 m

Also given that the Angle of elevation, ∠ACB = 600

Let’s consider the distance from base is X m

Now, from the triangle ACB:

∴  A group of students of class

By substituting values in above equation, we get:

A group of students of class

∵ we know that A group of students of class

∴  A group of students of class

A group of students of class = 14 x 1.732 = 24.248

Hence, option a) is correct.

3. Height of the vertical tower: 

A group of students of classFrom the adjoining figure, we can see that in ∆ ABC,

Given that the angle of elevation, ∠ACB = 600

Also given that the length of shadow = 20 m

Let’s consider the height of the tower is X m

Now, from the ∆ ACB:

∴  A group of students of class

By substituting values in above equation, we get:

A group of students of class

∵ we know that A group of students of class

A group of students of class

∴ X  = A group of students of class m

Hence, option a) is correct.

4.  Angle of elevation of the Sun:

A group of students of classwe can see that in ∆ ABC,

Height AB = Distance from the base, BC

Now, let’s consider that the ∠ ACB is A group of students of class,

∴  A group of students of class

By substituting values in above equation, we get:

A group of students of class

∵ we know that tan 450 = 1

A group of students of class

A group of students of class = 450

Hence, option b) is correct.

5. Angle Name:

A group of students of classWe know that the angle between the horizontal line and the object (when object is below the horizontal), is called angle of depression.

Hence, option c) is correct option. 

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