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Q) ABCD is a parallelogram. Point P divides AB in the ratio 2:3 and point Q divides DC in the ratio 4:1. Prove that OC is half of OA.

ABCD is a parallelogram. Point P
Ans: 

VIDEO SOLUTION

STEP BY STEP SOLUTION

Given that ABCD is a parallelogram.

Therefore, AB ǁ CD and BC ǁ AD

Step 1: Since, Point P divides AB in the ratio 2:3

Therefore, if AB = a, then:

AP = ABCD is a parallelogram. Point Pa

and BP = ABCD is a parallelogram. Point PaABCD is a parallelogram. Point P

Step 2: Similarly, Point Q divides CD in the ratio 4:1

Therefore, since CD = AB = a, then:

DQ = ABCD is a parallelogram. Point Pa

and QC = ABCD is a parallelogram. Point Pa

Step 3: Let’s look at Δ AOP and Δ QOC,

∠ AOP = ∠ QOC  (vertically opposite angles)ABCD is a parallelogram. Point P

∠ OAP = ∠ QCO    (interior angles)

By AA similarity rule,

Δ AOP ABCD is a parallelogram. Point P Δ QOC

ABCD is a parallelogram. Point P = ABCD is a parallelogram. Point P

Step 4: Let’s start substituting values of AP and QC from previous steps:

We calculated: AP = ABCD is a parallelogram. Point Pa and QC = ABCD is a parallelogram. Point Pa

ABCD is a parallelogram. Point P = ABCD is a parallelogram. Point P

ABCD is a parallelogram. Point P = ABCD is a parallelogram. Point P

OC = ABCD is a parallelogram. Point P OA

Therefore, it is proved that OC is half of OA.

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