Q) If Sin θ + cos θ = √3, then find the value of Sin θ . Cos θ Ans: Given that Sin θ + cos θ = √3 Let’s square on both sides => (Sin θ + cos θ)2 = (√3) 2 ⇒ Sin2 θ + Cos2 θ +2 Sin θ Cos θ = […]
If Sin θ + Cos θ = √3, then find the value of Sin θ . Cos θ Read More »
Q) In the given figure, XZ is parallel to BC. AZ = 3 cm, ZC = 2 cm, BM = 3 cm and MC = 5 cm. Find the length of XY. Ans: Since XZ ǁ BC, Therefore, (BPT Theorem) ∴ ………….. (i) Since XZ ǁ BC, ∴ XY ǁ BM ∠ AXY = ∠
Q) Solve the pair of equations x = 3 and y = – 4 graphically. Ans: VIDEO SOLUTION STEP BY STEP SOLUTION Step 1: Lets plot both the equations on the graph. Step 2: Increase till these lines intersect each other. We get the intersection point as (3,-4) Since the lines are intersecting at (3,
Solve the pair of equations x = 3 and y =- 4 graphically. Read More »
Class 10 Mathematics Chapter 1 – Real Numbers Exercise 1.2 1). Express each number as a product of its prime factors: (i) 140(ii) 156(iii) 3825(iv) 5005(v) 7429 Solution: (i) 140: To find the prime factorization of 140, we can use either trial division or prime decomposition (factor tree). Let’s use prime decomposition here: Factor tree
NCERT Solutions: Class 10 Mathematics Chapter 1 – Real Numbers Exercise 1.2 Read More »