Q) Find the mean and median of the following data:

Find the mean and median of the following data:
2025 SQP

Ans:

(i) Mean Value of data:

To calculate the mean value, let’s re-organize the data:

Find the mean and median of the following data: 2025 Sample Question Paper SQP 10th board exams

To arrange the above, we take following steps:

  • We calculate midpoint ‘x’of each class by \frac{lower~value + higher~value}{2}
  • Then we calculate ‘fx’ by multiplying midpoint of each class with frequency of that class
  • We calculate Σf by summing up all the frequencies and Σfx by adding up all the values of fx

Next, we know that, mean of grouped data is given by:

Mean of grouped data = (\frac{\sum f_x}{\sum f})

Therefore, Mean value = \frac{12105}{120} = 100.875

Hence, the mean value of the given data is 100.875

(ii) Median value of data:

To calculate the median value, let’s re-organize the data:

Find the mean and median of the following data:
2025 Sample Question Paper SQP 10th board exams

To find the median, we need to first identify middle class of the data.

  • We know that, Median class is the class where the cumulative frequency crosses 50% of total of frequencies.
  • Here, in the given data, total of frequencies is 120 and at row 4 cumulative frequency is crossing 50% of total (i.e. 60)
  • Hence, our Median class = 100-105

Next, the median value of a grouped data is given by:

Median = L+ \left [\frac{\frac{n}{2}-c_f}{f}\right] \times h

Here:

L = Lower boundary of the median class = 100

n = Total number of frequencies = 120

{c_f} = Cumulative frequency of the class before the median class = 57

f = Frequency of the median class = 18

h = Class width = 105 – 100 = 5

hence, the Median = 100 + \left [\frac{\frac{120}{2} - 57}{18}\right] \times 5

⇒ 100 + [(60 – 57)] x \frac{5}{18}

⇒ 100 + \frac{3 \times 5}{18}

⇒ 100 + 0.833

⇒ 100.833

Therefore, Median value of the grouped data is 100.833

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