Q) Find the ratio in which y-axis divides the line segment joining the points (5, – 6) and (- 1, – 4).

Ans: Let’s draw the diagram to solve:

Find the ratio in which CBSE important questions 10th board

Let’s consider the coordinates of point P is (0,y)

Also consider that the line AB is divided in ratio of m : n.

By section formula, if a point (x, y) divides the line joining the points (x1, y1​) and (x2​, y2​) in the ratio m : n, then coordinates of point (x, y) =
(\frac{mx_1 + nx_2}{m + n}, \frac{my_1 + ny_2}{m + n})

Here, it is given that

A (5, – 6) = (x1, y1​)

B (-1, – 4) = (x2​, y2​),

Let’s consider line is divided in the ratio of m : n

Hence the co-ordinates of point P:

x = \frac{(- m + 5 n)}{(m + n)} =  0

or m = 5 n

\frac {m}{n} = \frac{5}{1}

Therefore, the line is divided in the ratio of 5: 1.

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