Q) From a point on a bridge across the river, the angles of depressions of the banks on opposite sides of the river are 30° and 60° respectively. If the bridge is at a height of 4 m from the banks, find the width of the river.

Ans: 

Let’s start with a diagram for this given question:

From a point on a bridge across the river, the angles of depressions of the banks

Step 1: Let’s start with Δ ARP,

tan R = \frac{AP}{AR}

since AP = 4 m (given)

∴ tan 60 = \frac{4}{AR}

∴ √3 = \frac{4}{AR}

∴ AR = \frac{4}{\sqrt 3}

∴ AR = \frac{4 \sqrt 3}{3} ……….. (i)

Step 2: Next, let’s look at Δ BRQ,

tan R = \frac{BQ}{BR}

since BQ = 4 m (given)

∴ tan 30 = \frac{4}{BR}

\frac{1}{\sqrt 3} = \frac{4}{BR}

∴ BR = 4 √3 ……….. (ii)

Step 3: Next, from the diagram, we have:

Width of the river, AB = AR + BR

By substituting values of AR from equation (i) and value of BR from equation (ii)

AB = \frac{4 \sqrt 3}{3} + 4\sqrt 3

AB = (\frac{1}{3} + 1) 4\sqrt 3

AB = \frac{4}{3} 4\sqrt 3

AB = \frac{16}{3}\sqrt 3 m

By substituting √3 = 1.73, we get:

AB = \frac{16}{3} (1.73) = 9.23 m

Therefore, the width of the river is 9.23 m

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