Q)  From an aeroplane vertically above a straight horizontal road, the angles of depression of two consecutive mile stones on opposite sides of the aeroplane are observed to be α and β. Show that the height in miles of aeroplane above the road is given by tan α tan ẞ / (tan α + tan ẞ).

Ans: 

Step 1: Let’s draw a diagram for the given question:

From an aeroplane vertically above a straight horizontal road, the angles of depression of two consecutive mile stones on opposite 10th board exam PYQ important question

Let AB or h be the height of the plane; , P and Q be the milestones and angles of depression be α and β respectively.

Also distance between PQ and is 1 mile (for being consecutive milestones). We need to find the height h.

Here, ∠ P will be equal to α and ∠ Q will be equal to β (for being, alternate interior angles)

Step 2: In Δ  ABP, tan P = \frac{BA}{PA}

∴ tan α = \frac{h}{PA}

∴ PA = \frac{h}{\tan \alpha} ………….. (i)

Step 3: In Δ  ABQ, tan Q = \frac{BA}{AQ}

∴ tan β = \frac{h}{AQ}

∴ AQ = \frac{h}{\tan \beta} ………….. (ii)

Step 4: From the diagram, we can see that PQ = PA + AQ

By substituting values of PA & AQ from equations (i) and (ii), respectively, we get:

PQ = PA + AQ

∴ D = \frac{h}{\tan \alpha} + \frac{h}{\tan \beta}

∴ D = \frac{h \tan \alpha + h \tan \beta} {\tan \alpha \tan \beta}

∴ D = \frac{h (\tan \alpha + \tan \beta)} {\tan \alpha \tan \beta}

Since it is given that D = 1

∴ 1 = \frac{h (\tan \alpha + \tan \beta)} {\tan \alpha \tan \beta}

∴  h = \frac {\tan \alpha \tan \beta}{(\tan \alpha + \tan \beta)}

Hence Proved !

Please press “Heart” button if you like the solution. 

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top