Q) If Q(0,1) is equidistant from P(5,-3) and R (x,6), find the values of x.

Ans:

since the Point Q is equidistant, then

Distance between P & Q = Distance between R & Q

\therefore  (5-0) 2 + (-3-1) 2 = (x-0)2 + (6-1)2

or 25 +16 = x2 + 25

or x2 = 16

or x = 4, x = -4

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