Q) If Q(0,1) is equidistant from P(5,-3) and R (x,6), find the values of x.
Ans:
since the Point Q is equidistant, then
Distance between P & Q = Distance between R & Q
(5-0) 2 + (-3-1) 2 = (x-0)2 + (6-1)2
or 25 +16 = x2 + 25
or x2 = 16
or x = 4, x = -4
Related Math Questions
- Solve the following system of linear equations graphically: 3 x – y + 1 = 0 View Detailed Solution »
- The vertices of a quadrilateral ABCD are A(6, – 2), B(9, 2), C(5, – 1) and D(2, – 5). View Detailed Solution »
- In what ratio does the X-axis divide the line segment joining the points(2, –3) and (5, 6)? View Detailed Solution »
- 26 b. Prove that the point P dividing the line segment joining the points A (- 1, 7) and B (4, – 3) in the ratio 3: 2, lies on the line x – 3y = – 1. Also find length of PA and PB. View Detailed Solution »