Q) If sin (A – B) = \frac{1}{2}, cos (A + B) = \frac{1}{2}; 0 < A + B <= 90°, A > B; find ∠ A and ∠ B.

Ans: Let’s take the components one by one:

Step 1: sin (A – B) = \frac{1}{2}

Since we know that sin 300 = \frac{1}{2}

∴ sin (A – B) = sin 300

∴ A – B = 30…… (i)

Step 2: cos (A + B) = \frac{1}{2};

Since we know that cos 600 = \frac{1}{2}

∴ cos (A + B) = cos 600

∴ A + B = 600   …… (ii)

Step 3: By adding equation (i) and (ii), we get:

∴ (A – B) + (A + B) = 300 + 600

∴ 2 A = 900

∴ A = \frac{90}{2} = 450

By putting the value of A into equation (i), we get:

A – B = 30

∴ 450 – B = 300

∴ B = 450 – 300

∴ B = 150

Therefore the values of A is 450 and value of B is 150 .

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