Q) In what ratio does the X-axis divide the line segment joining the points(2, – 3) and (5, 6)? Also, find the coordinates of the point of intersection.

Ans: Let’s draw the diagram to solve:

In what ratio does the X-axis divide the line segment joining the points(2, –3) and (5, 6)?

(i) Ratio of division:

We know that the value of y-coordinate on X- axis is always 0

It is given that X-axis intersects the line connecting points P &Q, hence the value of y-coordinate of intersection point A will be 0.

∴ we can consider the coordinates of point A as (x, 0)

Next, let’s consider that the line PQ is divided in the ratio of m : n.

We know that, by section formula, if a point (x, y) divides the line joining the points (x1, y1​) and (x2​, y2​) in the ratio m : n, then the coordinates of intersection point (x, y) is given by:

(\frac{m x_1 + n x_2}{m + n}, \frac{m y_1 + n y_2}{m + n})

Here, it is given that

P (2, – 3) = (x1, y1​)

Q (5, 6) = (x2​, y2​),

Let’s consider line is divided in the ratio of m : n

Hence the y-coordinate of point A:

y = \frac{m (- 3) + n (6)}{(m + n)}

∴  0 = \frac{m (- 3) + n (6)}{(m + n)}

∴ – 3 m + 6 n = 0 

∴ 3 m = 6 n

∴ m = 2 n

∴ m : n = 2 : 1

Therefore, the line is divided in the ratio of 2 : 1.

(ii) Coordinates of intersection point:

From the section formula, let’s find the value of x coordinate:

x = \frac{m_1 \times_1 + m_2 \times_2}{m + n}

∴ x = \frac{(2) (2) + (1)(5)}{2 + 1}

∴ x = \frac {9}{3} = 3

Since, value of y coordinate is 0 (being on X-axis)

Therefore the coordinates of intersection point A are (3, 0).

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