Q) Prove that 3√2 is an irrational number.
Ans: Let us assume that 3√2 is a rational number
Then we can represent 3√2 as 
; where q ≠ 0 and let p, q are co-primes.
3√2 = ………………. (i)
or it can be rearranged as √2 = 
Since, 3, a and b are integers,
is a rational number.
Hence, √2 is rational.
But it contradicts the fact that √2 is a irrational number;
Therefore, 3√2 is an irrational number………… Hence Proved !