Q) Reena has a 10 m × 10 m kitchen garden attached to her kitchen. She divides it into a 10 × 10 grid and wants to grow some vegetables and herbs used in the kitchen. She puts some soil and manure in that and sow a green chilly plant at A, a coriander plant at B and a tomato plant at C. Her friend Kavita visited the garden and praised the plants grown there. She pointed out that they seem to be in a straight line. See the below diagram carefully:

Reena has a 10 m × 10 m kitchen garden

i. Find the distance between A and B.
ii. Find the mid-point of the distance AB.
iii. Find the distance between B and C.
iv. Find the mid point of BC.

Ans:

1. Distance between A and B:

Step 1: From the diagram, Coordinates of point A: (2, 2)

Coordinates of point B: (5, 4)

Step 2: We know that the distance between two points P (X1, Y1) and Q (X2, Y2) is given by:

PQ = \sqrt {(\times_2 - \times _1)^2 + (Y_2 - Y_1)^2}

∴ Distance AB = \sqrt{(5 - 2)^2 + (4 - 2)^2}

∴ AB = \sqrt{9 + 4}

∴ AB = \sqrt{13}

Therefore, the distance between points A and B is 13 m.

2. Mid point of AB:

Step 3: Now we have coordinates of point A (2, 2) and Point B (5, 4)

∵ We know that the coordinates of midpoint of 2 coordinates (X1, Y1) and (X2, Y2) given by:

(X, Y) = (\frac{(X_1 + X_2)}{2}, \frac{(Y_1 + Y_2)}{2})

∴ Coordinates of midpoint of A (2, 2) and B (5, 4) = (\frac{(2 + 5)}{2}, \frac{(2 + 4)}{2})

= (\frac{7}{2}, 3)

Therefore, the coordinates of midpoint of AB are (\frac{7}{2}, 3).

3. Distance between B and C:

Step 4: From the diagram, Coordinates of point B: (5, 4)

Coordinates of point C: (7, 6)

Step 5: By putting values in distance formula (explained in step 2), we get:

∴ Distance BC = \sqrt{(7 - 5)^2 + (6 - 4)^2}

∴ AB = \sqrt{4 + 4}

∴ AB = 2\sqrt{2}

Therefore, the distance between points A and B is 2 √2 m.

4. Mid point of BC:

Step 3: Now we have coordinates of point B (5, 4) and Point C (7, 6)

By putting values in distance formula (explained in step 3), we get:

Coordinates of midpoint of B (5, 4) and C (7, 6) = (\frac{(5 + 7)}{2}, \frac{(4 + 6)}{2})

= (\frac{12}{2}, \frac{10}{2}) = (6, 5)

Therefore, the coordinates of midpoint of AB are (6, 5).

Please press the “Heart”, if you liked the solution.

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top