Q) Show that the points A(-5,6), B(3, 0) and C( 9, 8) are the vertices of an isosceles triangle.
Ans:
For a triangle to be an isosceles triangle, its any 2 sides should be equal.
Let’s start by calculating length of its sides:
We know that the distance between two points P (X1, Y1) and Q (X2, Y2) is given by:
PQ = ![]()
We have coordinates as A(-5,6), B(3, 0) and C( 9, 8)
β΄ AB = ![]()
β΄ AB = ![]()
β΄ AB = ![]()
β΄ AB = 10
Similarly, BC = ![]()
β΄ BC =Β ![]()
β΄ BC = ![]()
β΄ BC = 10
Here, since AB = BC
Therefore, A, B and C are vertices of an isosceles triangle.
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