Q. Solve for X :
Ans: Given equation is:
∴
∴ 4 (2 X + 3) – 5 X = 3 X (2X + 3)
∴ 8 X + 12 – 5 X = 6 X 2 + 9 X
∴ 12 = 6 X 2 + 6 X
∴ 6 X 2 + 6 X – 12 = 0
∴ X 2 + X – 2 = 0
∴ X 2 + 2 X – X – 2 = 0
∴ X ( X + 2) – 1 (X + 2) = 0
∴ (X + 2) (X – 1) = 0
∴ X = 1 and X = – 2
Therefore values of X are 1 and – 2
Check: Let’s check our answers:
at X = 1 in LHS, equation will become:
= 4 – = 4 – 1 = 3
at X = – 2 in LHS, equation will become:
= – 2 – = – 2 + 5 = 3
Since values of LHS matches with given value on RHS, our both answers are correct.
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