Q) The maturity value of a R.D account is Rs. 16,176. If monthly investment is Rs. 400 and the rate of interest is 8%, find the time (period) of this R.D. Account.

Ans: Given that:

Monthly Instalment, P = Rs. 400

Rate of Interest, r = 8 %

Maturity value of RD account = Rs. 16, 176

Step 1: Let’s consider the time period is n months

We know that Interest Amount, I = P × \frac{n (n + 1)}{2} \times \frac{r}{12 \times 100}

= 400 × \frac{n (n + 1)}{2} \times \frac{8}{12 \times 100}

= \frac{4}{3} × n (n + 1)

Step 2: Since, Monthly instalment, P = Rs. 400 (given)

and Number of months invested = n

∴ Total investment = n x P = n x 400 = 400 n

Step 3: We know that, Maturity value of RD account = Total investment + Interest Amount

∴ 16176 = 400 n + \frac{4}{3} × n (n + 1)

∴ 16176 x 3 = 400 n x 3 + 4 (n 2 + n)

∴ 48528 = 1200 n + 4 n 2 + 4n

∴ 4 n 2 + 1204 n – 48528 = 0

∴ n 2 + 301 n – 12132 = 0

∴ n 2 + 337 n – 36 n – 12132 = 0

∴ n (n + 337) – 36 (n + 337) = 0

∴ (n + 337) (n – 36) = 0

∴ n = 36 and n = – 337

Here, we reject n = – 337 because months value can not be negative, hence n = 36

hence, time period, n = 36 months = 3 years

Therefore, time period of RD account is 36 months or 3 years.

Check: For time period of 36 months, money invested is 400 x 36 = 14400

Interest Amount, I = P × \frac{n (n + 1)}{2} \times \frac{r}{12 \times 100}

= 400 x \frac{36 (36 + 1)}{2} \times \frac{8}{12 \times 100}

= 400 x 18 x 37 x \frac{2}{300}

= 4 x 6 x 37 x 2 = 1776

Total maturity amount = 14400 + 1776 = 16176

Since it matches the given maturity amount in question, hence our answer is correct.

Please press the “Heart”, if you liked the solution.

Leave a Comment

Your email address will not be published. Required fields are marked *

Scroll to Top